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<br />In an attempt to find the amount of crop saved due to hail <br />suppression we know the Estimated crop Hail Loss (ECHL) must be <br />smaller than what the total crop hail loss would be had there been <br />no cloud seeding. NOTE: This implies that hail suppression works to <br />some degree or another. We will call the Total Crop Hail Loss <br />(TCHL). Mathematically it is represented as: <br /> <br />TCHL = ECHL + (TCHL) x (P) <br /> <br />Where P is the expected percentage decrease in hail, then <br /> <br />and, <br /> <br />TCHL - [(TCHL) x P] = ECHL <br />TCHL(l - P) = ECHL <br /> <br />or <br /> <br />TCHL = <br /> <br />(ECHL) <br />(1 - P) <br /> <br />Then, <br /> <br />Crop Saved = TCHL - ECHL <br /> <br />or, substituting <br /> <br />Crop Saved = <br /> <br />IECHL) <br />(1 - P) <br /> <br />(ECHL) <br /> <br />and <br /> <br />Crop Saved = <br /> <br />IECHL) x f1 - II - P)) <br />(1 - P) <br /> <br />clearing terms, <br /> <br />Crop Saved = (ECHL) x I P ) <br />(1 - P) <br /> <br />For instance, if we assume there was as little as a 10% <br /> <br />reduction in hail, then, <br /> <br />Crop Saved = (EHCL) x 10.1) = (ECHLl <br />(0.9) 9 <br /> <br />, <br /> <br />for a 20% reduction, Crop Saved = (EHCL) x 10.2) = IEHCL) <br />0.3 4 <br /> <br />for a 25% reduction, Crop Saved = IEHCL) <br />3 <br /> <br />for a 30% reduction, Crop Saved = (.30) x (EHCL) = (3/7) x (EHCL) <br />(1 - 0.3) <br /> <br />and for a 35% reduction the Crop Saved = (7/13) x (EHCL) <br /> <br />47 <br />