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Last modified
7/14/2009 5:02:32 PM
Creation date
5/20/2009 10:54:46 AM
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UCREFRP
UCREFRP Catalog Number
8033
Author
Lentsch, L. D., et al.
Title
Endangered Fish Interim Management Objectives for the Upper Colorado River Basin Recovery And Implementation Program -Final Report.
USFW Year
1998.
USFW - Doc Type
55,
Copyright Material
NO
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<br />Calculating Nm <br />' The estimates of N. were divided into three general calculations by accounting for 1) biased sex <br />ratio, 2) Ne/N and 3) population demographic stability. The minimum value of Ne was set at 1000 <br />for all species and populations (Table 6). This value served as the initial value for the calculations. <br />Step 1. Accounting for a biased sex ratio (estimates of NO <br />' The following formulas were used to estimate the number of breeding individuals (Nb) required to <br />maintain the given Ne (1000): <br />N. = 4MbFb/Mb+Fb [1] (Wright 1931) <br />Nb = Mb + Fb [2] <br />where, <br />Mb = number of breeding males <br />Fb = number of breeding females <br />When the number of breeding individuals (Nb) equals the number of individuals contributing genes <br />' to the next generation (N), then N. = Nb. However, when the genetic contribution is biased by <br />males or females, N. is reduced by an amount depending on how much the sex ratio is biased. <br />That is, the greater the bias, the greater the reduction in Ne. To maintain a minimum Ne of 1000 <br />when a species has a biased sex ratio (eg. 3: 1), Nb would be larger than N. <br />(ie. Nb> 1000). For <br />example: <br />Based on a 1:1 sex ratio; <br />Nb = 1000 then Mb = 500 and Mf= 500 and, based on equation [1], <br />Ne = 4(500)(500)/(500+500) = 1000 <br />Based on a 3:1 sex ratio; <br />Nb = 1000 and Mb = 750 and Fb = 250 and , based on equation [1 <br />Ne = 4(750)(250)/750 + 250 = 750 <br />To account for the 25% loss in Ne the total number of breeding adults (Nb) must be increased. <br />The number of breeding adults (Nb) needed to maintain an Ne of 1000 in a population with a 3:1 <br />sex ratio is 1330 (Table 6). That is; <br />Mb = 998 and Fb = 332 and, based on equation [1] <br />Ne = 4(998)(332)/1330 = 996 (approximately 1000) <br />Nb = (998+332) = 1330 <br />' Step 2. Accounting for a less than 100% contribution by all adults (estimates of N <br />A constant value of 0.5 for Ne/N is being used here based on suggestions by Nunney (1995) which <br />is slightly higher than the average for fish in Table 3. This means that only one-half of the adults in <br />the population are contributing offspring. To ensure that enough individuals are available to <br />maintain an N. of 1000 the final value calculated in Step 1(Nb) was doubled. In this example, <br />' Nb 1330 and Ng= 2660 (Table 6). <br />16 <br />
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