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<br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br />I <br /> <br /> TABLE 5-8: PUMPING HOURS REQUIRED TO MEET PEAK MONTHLY <br /> AND SEASONAL CROP IRRIGATION REQUIREMENTS <br /> FOR WHEAT FOR 122 ACRE PIVOT <br /> WELL HOURS TO MEET PEAK HOURS REQUIRED TO MEET <br /> CAPACITY, MONTHLY DEMAND (49.2 SEASONAL WATER <br /> REQUIREMENT (129 ACRE-FEET) <br /> GPM ACRE-FEET) FOR WHEATl FOR WHEAT2 <br /> 500 534 1401 <br /> 550 486 1274 <br /> 600 445 1168 <br /> 650 411 1078 <br /> 700 382 1001 <br /> 750 356 934 <br /> 800 334 876 <br /> 850 314 824 <br /> 900 297 778 <br />Footnotes <br />1. The peak monthly demand for wheat as determined by using the Blaney-Criddle <br /> method was determined to be 4.11 inches for May, see Table 5-2. The volume of <br /> water required to meet that demand is estimated to be 4.84 inches during the month <br /> of May, assuming an irrigation efficiency of 85 percent (4.11 inches/0.85). This is <br /> equivalent to 49.2 acre-feet for a 122-acre center pivot (4.84 inches x 122 acres/12 <br /> inches/ft.). <br />2. The number of hours required to operate an irrigation well to satisfy the seasonal <br /> water requirement for wheat is determined by dividing the total volume, 1.06 acrefeet <br /> per acre (0.9 acre-feet per acre, presented in Table 5-2 divided by an irrigation <br /> efficiency of 85 percent). Based upon this seasonal requirement, a 122-acre pivot will <br /> require 129 acre-feet per season (1.06 ac. ft.lacre x 122 acres). <br /> <br />V-12 <br />